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(6x-1)(x+2)=2
We move all terms to the left:
(6x-1)(x+2)-(2)=0
We multiply parentheses ..
(+6x^2+12x-1x-2)-2=0
We get rid of parentheses
6x^2+12x-1x-2-2=0
We add all the numbers together, and all the variables
6x^2+11x-4=0
a = 6; b = 11; c = -4;
Δ = b2-4ac
Δ = 112-4·6·(-4)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{217}}{2*6}=\frac{-11-\sqrt{217}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{217}}{2*6}=\frac{-11+\sqrt{217}}{12} $
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