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(6x-1)(x-10)=0
We multiply parentheses ..
(+6x^2-60x-1x+10)=0
We get rid of parentheses
6x^2-60x-1x+10=0
We add all the numbers together, and all the variables
6x^2-61x+10=0
a = 6; b = -61; c = +10;
Δ = b2-4ac
Δ = -612-4·6·10
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-59}{2*6}=\frac{2}{12} =1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+59}{2*6}=\frac{120}{12} =10 $
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