(6x-1)/(3-2x)=5

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Solution for (6x-1)/(3-2x)=5 equation: 



(6x-1)/(3-2x)=5

We move all terms to the left:

(6x-1)/(3-2x)-(5)=0



Domain of the equation: (3-2x)!=0

We move all terms containing x to the left, all other terms to the right

-2x!=-3

x!=-3/-2

x!=1+1/2

x∈R



We add all the numbers together, and all the variables

(6x-1)/(-2x+3)-5=0

We multiply all the terms by the denominator


(6x-1)-5*(-2x+3)=0

We multiply parentheses

(6x-1)+10x-15=0

We get rid of parentheses

6x+10x-1-15=0

We add all the numbers together, and all the variables

16x-16=0

We move all terms containing x to the left, all other terms to the right

16x=16

x=16/16

x=1

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