(6x-1)/(3-2x)=5

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Solution for (6x-1)/(3-2x)=5 equation:



(6x-1)/(3-2x)=5
We move all terms to the left:
(6x-1)/(3-2x)-(5)=0
Domain of the equation: (3-2x)!=0
We move all terms containing x to the left, all other terms to the right
-2x!=-3
x!=-3/-2
x!=1+1/2
x∈R
We add all the numbers together, and all the variables
(6x-1)/(-2x+3)-5=0
We multiply all the terms by the denominator
(6x-1)-5*(-2x+3)=0
We multiply parentheses
(6x-1)+10x-15=0
We get rid of parentheses
6x+10x-1-15=0
We add all the numbers together, and all the variables
16x-16=0
We move all terms containing x to the left, all other terms to the right
16x=16
x=16/16
x=1

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