(6x-1)/42=(10x+5)/78

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Solution for (6x-1)/42=(10x+5)/78 equation: 



(6x-1)/42=(10x+5)/78

We move all terms to the left:

(6x-1)/42-((10x+5)/78)=0

We calculate fractions


6x/()+(-((10x+5)*42)/()=0



We calculate terms in parentheses: +(-((10x+5)*42)/(), so:

-((10x+5)*42)/(

We multiply all the terms by the denominator


-((10x+5)*42)



We calculate terms in parentheses: -((10x+5)*42), so:

(10x+5)*42

We multiply parentheses

420x+210

Back to the equation:

-(420x+210)



We get rid of parentheses

-420x-210

Back to the equation:

+(-420x-210)



We get rid of parentheses

6x/()-420x-210=0

We multiply all the terms by the denominator


6x-420x*()-210*()=0

We add all the numbers together, and all the variables

6x-420x*()=0

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