(6x-10)(4x+20)=0

Solution for (6x-10)(4x+20)=0 equation:

(6x-10)(4x+20)=0

We multiply parentheses ..

(+24x^2+120x-40x-200)=0

We get rid of parentheses

24x^2+120x-40x-200=0

We add all the numbers together, and all the variables

24x^2+80x-200=0

a = 24; b = 80; c = -200;
Δ = b2-4ac
Δ = 802-4·24·(-200)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-160}{2*24}=\frac{-240}{48}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+160}{2*24}=\frac{80}{48}
=1+2/3
$