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(6x-10)(6x+10)=0
We use the square of the difference formula
36x^2-100=0
a = 36; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·36·(-100)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*36}=\frac{-120}{72} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*36}=\frac{120}{72} =1+2/3 $
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