(6x-10)+J=180

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Solution for (6x-10)+J=180 equation: 



(6x-10)+=180

We move all terms to the left:

(6x-10)+-(180)=0

determiningTheFunctionDomain
(6x-10)-180+=0

We add all the numbers together, and all the variables

(6x-10)=0

We get rid of parentheses

6x-10=0

We move all terms containing x to the left, all other terms to the right

6x=10

x=10/6

x=1+2/3

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