(6x-10)/(2x-5)=3

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Solution for (6x-10)/(2x-5)=3 equation: 


D( x )

2*x-5 = 0

2*x-5 = 0

2*x-5 = 0

2*x-5 = 0 // + 5

2*x = 5 // : 2

x = 5/2

x in (-oo:5/2) U (5/2:+oo)

(6*x-10)/(2*x-5) = 3 // - 3

(6*x-10)/(2*x-5)-3 = 0

(6*x-10)/(2*x-5)+(-3*(2*x-5))/(2*x-5) = 0

6*x-3*(2*x-5)-10 = 0

5 = 0

5/(2*x-5) = 0

5/(2*x-5) = 0 // * 2*x-5

5 = 0

x belongs to the empty set

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