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(6x-10)=(4x+12)
We move all terms to the left:
(6x-10)-((4x+12))=0
We get rid of parentheses
6x-((4x+12))-10=0
We calculate terms in parentheses: -((4x+12)), so:We get rid of parentheses
(4x+12)
We get rid of parentheses
4x+12
Back to the equation:
-(4x+12)
6x-4x-12-10=0
We add all the numbers together, and all the variables
2x-22=0
We move all terms containing x to the left, all other terms to the right
2x=22
x=22/2
x=11
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