(6x-11)(2x+5)=3x(4x+3)

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Solution for (6x-11)(2x+5)=3x(4x+3) equation: 



(6x-11)(2x+5)=3x(4x+3)

We move all terms to the left:

(6x-11)(2x+5)-(3x(4x+3))=0

We multiply parentheses ..

(+12x^2+30x-22x-55)-(3x(4x+3))=0



We calculate terms in parentheses: -(3x(4x+3)), so:

3x(4x+3)

We multiply parentheses

12x^2+9x

Back to the equation:

-(12x^2+9x)



We get rid of parentheses

12x^2-12x^2+30x-22x-9x-55=0

We add all the numbers together, and all the variables

-1x-55=0

We move all terms containing x to the left, all other terms to the right

-x=55

x=55/-1

x=-55

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