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(6x-12)(6x+39)=0
We multiply parentheses ..
(+36x^2+234x-72x-468)=0
We get rid of parentheses
36x^2+234x-72x-468=0
We add all the numbers together, and all the variables
36x^2+162x-468=0
a = 36; b = 162; c = -468;
Δ = b2-4ac
Δ = 1622-4·36·(-468)
Δ = 93636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{93636}=306$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(162)-306}{2*36}=\frac{-468}{72} =-6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(162)+306}{2*36}=\frac{144}{72} =2 $
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