(6x-12)/2=(3x+24)/11

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Solution for (6x-12)/2=(3x+24)/11 equation: 



(6x-12)/2=(3x+24)/11

We move all terms to the left:

(6x-12)/2-((3x+24)/11)=0

We calculate fractions


6x/()+(-((3x+24)*2)/()=0



We calculate terms in parentheses: +(-((3x+24)*2)/(), so:

-((3x+24)*2)/(

We multiply all the terms by the denominator


-((3x+24)*2)



We calculate terms in parentheses: -((3x+24)*2), so:

(3x+24)*2

We multiply parentheses

6x+48

Back to the equation:

-(6x+48)



We get rid of parentheses

-6x-48

Back to the equation:

+(-6x-48)



We get rid of parentheses

6x/()-6x-48=0

We multiply all the terms by the denominator


6x-6x*()-48*()=0

We add all the numbers together, and all the variables

6x-6x*()=0

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