(6x-12)/2=(3x+24)/11

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Solution for (6x-12)/2=(3x+24)/11 equation:



(6x-12)/2=(3x+24)/11
We move all terms to the left:
(6x-12)/2-((3x+24)/11)=0
We calculate fractions
6x/()+(-((3x+24)*2)/()=0
We calculate terms in parentheses: +(-((3x+24)*2)/(), so:
-((3x+24)*2)/(
We multiply all the terms by the denominator
-((3x+24)*2)
We calculate terms in parentheses: -((3x+24)*2), so:
(3x+24)*2
We multiply parentheses
6x+48
Back to the equation:
-(6x+48)
We get rid of parentheses
-6x-48
Back to the equation:
+(-6x-48)
We get rid of parentheses
6x/()-6x-48=0
We multiply all the terms by the denominator
6x-6x*()-48*()=0
We add all the numbers together, and all the variables
6x-6x*()=0

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