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(6x-12)/3-x=3x-(x+1)+1
We move all terms to the left:
(6x-12)/3-x-(3x-(x+1)+1)=0
We add all the numbers together, and all the variables
-1x+(6x-12)/3-(3x-(x+1)+1)=0
We multiply all the terms by the denominator
-1x*3+(6x-12)-((3x-(x+1)+1))*3=0
Wy multiply elements
-3x+(6x-12)-((3x-(x+1)+1))*3=0
We get rid of parentheses
-3x+6x-((3x-(x+1)+1))*3-12=0
We add all the numbers together, and all the variables
3x-((3x-(x+1)+1))*3-12=0
We move all terms containing x to the left, all other terms to the right
3x-((3x-(x+1)+1))*3=12
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