(6x-12)=(2x+16)+(2x+10)

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Solution for (6x-12)=(2x+16)+(2x+10) equation: 



(6x-12)=(2x+16)+(2x+10)

We move all terms to the left:

(6x-12)-((2x+16)+(2x+10))=0

We get rid of parentheses

6x-((2x+16)+(2x+10))-12=0



We calculate terms in parentheses: -((2x+16)+(2x+10)), so:

(2x+16)+(2x+10)

We get rid of parentheses

2x+2x+16+10

We add all the numbers together, and all the variables

4x+26

Back to the equation:

-(4x+26)



We get rid of parentheses

6x-4x-26-12=0

We add all the numbers together, and all the variables

2x-38=0

We move all terms containing x to the left, all other terms to the right

2x=38

x=38/2

x=19

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