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(6x-12)=(3x+3)
We move all terms to the left:
(6x-12)-((3x+3))=0
We get rid of parentheses
6x-((3x+3))-12=0
We calculate terms in parentheses: -((3x+3)), so:We get rid of parentheses
(3x+3)
We get rid of parentheses
3x+3
Back to the equation:
-(3x+3)
6x-3x-3-12=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5
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