(6x-12)=4(x+1)-2

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Solution for (6x-12)=4(x+1)-2 equation: 



(6x-12)=4(x+1)-2

We move all terms to the left:

(6x-12)-(4(x+1)-2)=0

We get rid of parentheses

6x-(4(x+1)-2)-12=0



We calculate terms in parentheses: -(4(x+1)-2), so:

4(x+1)-2

We multiply parentheses

4x+4-2

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We get rid of parentheses

6x-4x-2-12=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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