(6x-12)=4(x+1)-2

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Solution for (6x-12)=4(x+1)-2 equation:



(6x-12)=4(x+1)-2
We move all terms to the left:
(6x-12)-(4(x+1)-2)=0
We get rid of parentheses
6x-(4(x+1)-2)-12=0
We calculate terms in parentheses: -(4(x+1)-2), so:
4(x+1)-2
We multiply parentheses
4x+4-2
We add all the numbers together, and all the variables
4x+2
Back to the equation:
-(4x+2)
We get rid of parentheses
6x-4x-2-12=0
We add all the numbers together, and all the variables
2x-14=0
We move all terms containing x to the left, all other terms to the right
2x=14
x=14/2
x=7

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