(6x-18)(-3x-24)=0

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Solution for (6x-18)(-3x-24)=0 equation:



(6x-18)(-3x-24)=0
We multiply parentheses ..
(-18x^2-144x+54x+432)=0
We get rid of parentheses
-18x^2-144x+54x+432=0
We add all the numbers together, and all the variables
-18x^2-90x+432=0
a = -18; b = -90; c = +432;
Δ = b2-4ac
Δ = -902-4·(-18)·432
Δ = 39204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{39204}=198$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-198}{2*-18}=\frac{-108}{-36} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+198}{2*-18}=\frac{288}{-36} =-8 $

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