(6x-2)(5+x)=0

Solution for (6x-2)(5+x)=0 equation:

(6x-2)(5+x)=0

We add all the numbers together, and all the variables

(6x-2)(x+5)=0

We multiply parentheses ..

(+6x^2+30x-2x-10)=0

We get rid of parentheses

6x^2+30x-2x-10=0

We add all the numbers together, and all the variables

6x^2+28x-10=0

a = 6; b = 28; c = -10;
Δ = b2-4ac
Δ = 282-4·6·(-10)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-32}{2*6}=\frac{-60}{12}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+32}{2*6}=\frac{4}{12}
=1/3
$