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(6x-2)(x-1)=0
We multiply parentheses ..
(+6x^2-6x-2x+2)=0
We get rid of parentheses
6x^2-6x-2x+2=0
We add all the numbers together, and all the variables
6x^2-8x+2=0
a = 6; b = -8; c = +2;
Δ = b2-4ac
Δ = -82-4·6·2
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4}{2*6}=\frac{4}{12} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4}{2*6}=\frac{12}{12} =1 $
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