(6x-2)+(4x+3)=180

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Solution for (6x-2)+(4x+3)=180 equation: 



(6x-2)+(4x+3)=180

We move all terms to the left:

(6x-2)+(4x+3)-(180)=0

We get rid of parentheses

6x+4x-2+3-180=0

We add all the numbers together, and all the variables

10x-179=0

We move all terms containing x to the left, all other terms to the right

10x=179

x=179/10

x=17+9/10

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