(6x-2)-(3x+4)=15

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Solution for (6x-2)-(3x+4)=15 equation: 



(6x-2)-(3x+4)=15

We move all terms to the left:

(6x-2)-(3x+4)-(15)=0

We get rid of parentheses

6x-3x-2-4-15=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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