(6x-2)/2=(7x+9)/3

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Solution for (6x-2)/2=(7x+9)/3 equation: 



(6x-2)/2=(7x+9)/3

We move all terms to the left:

(6x-2)/2-((7x+9)/3)=0

We calculate fractions


6x/()+(-((7x+9)*2)/()=0



We calculate terms in parentheses: +(-((7x+9)*2)/(), so:

-((7x+9)*2)/(

We multiply all the terms by the denominator


-((7x+9)*2)



We calculate terms in parentheses: -((7x+9)*2), so:

(7x+9)*2

We multiply parentheses

14x+18

Back to the equation:

-(14x+18)



We get rid of parentheses

-14x-18

Back to the equation:

+(-14x-18)



We get rid of parentheses

6x/()-14x-18=0

We multiply all the terms by the denominator


6x-14x*()-18*()=0

We add all the numbers together, and all the variables

6x-14x*()=0

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