(6x-2)=4/5(10x-5)+43

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Solution for (6x-2)=4/5(10x-5)+43 equation: 



(6x-2)=4/5(10x-5)+43

We move all terms to the left:

(6x-2)-(4/5(10x-5)+43)=0



Domain of the equation: 5(10x-5)+43)!=0

x∈R



We get rid of parentheses

6x-(4/5(10x-5)+43)-2=0

We multiply all the terms by the denominator


6x*5(10x-5)-2*5(10x-5)+43)-(4+43)=0

We add all the numbers together, and all the variables

6x*5(10x-5)-2*5(10x-5)+43)-47=0

We add all the numbers together, and all the variables

6x*5(10x-5)-2*5(10x-5)=0

Wy multiply elements

30x^2(1-10x(1=0

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