(6x-3)(2x+1)=

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Solution for (6x-3)(2x+1)= equation:


Simplifying
(6x + -3)(2x + 1) = 0

Reorder the terms:
(-3 + 6x)(2x + 1) = 0

Reorder the terms:
(-3 + 6x)(1 + 2x) = 0

Multiply (-3 + 6x) * (1 + 2x)
(-3(1 + 2x) + 6x * (1 + 2x)) = 0
((1 * -3 + 2x * -3) + 6x * (1 + 2x)) = 0
((-3 + -6x) + 6x * (1 + 2x)) = 0
(-3 + -6x + (1 * 6x + 2x * 6x)) = 0
(-3 + -6x + (6x + 12x2)) = 0

Combine like terms: -6x + 6x = 0
(-3 + 0 + 12x2) = 0
(-3 + 12x2) = 0

Solving
-3 + 12x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 12x2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 12x2 = 0 + 3
12x2 = 0 + 3

Combine like terms: 0 + 3 = 3
12x2 = 3

Divide each side by '12'.
x2 = 0.25

Simplifying
x2 = 0.25

Take the square root of each side:
x = {-0.5, 0.5}

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