(6x-3)(2x+1)=12

Solution for (6x-3)(2x+1)=12 equation:

Simplifying
(6x + -3)(2x + 1) = 12

Reorder the terms:
(-3 + 6x)(2x + 1) = 12

Reorder the terms:
(-3 + 6x)(1 + 2x) = 12

Multiply (-3 + 6x) * (1 + 2x)
(-3(1 + 2x) + 6x * (1 + 2x)) = 12
((1 * -3 + 2x * -3) + 6x * (1 + 2x)) = 12
((-3 + -6x) + 6x * (1 + 2x)) = 12
(-3 + -6x + (1 * 6x + 2x * 6x)) = 12
(-3 + -6x + (6x + 12x2)) = 12

Combine like terms: -6x + 6x = 0
(-3 + 0 + 12x2) = 12
(-3 + 12x2) = 12

Solving
-3 + 12x2 = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 12x2 = 12 + 3

Combine like terms: -3 + 3 = 0
0 + 12x2 = 12 + 3
12x2 = 12 + 3

Combine like terms: 12 + 3 = 15
12x2 = 15

Divide each side by '12'.
x2 = 1.25

Simplifying
x2 = 1.25

Take the square root of each side:
x = {-1.118033989, 1.118033989}