(6x-3)(4+2x)=0

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Solution for (6x-3)(4+2x)=0 equation:



(6x-3)(4+2x)=0
We add all the numbers together, and all the variables
(6x-3)(2x+4)=0
We multiply parentheses ..
(+12x^2+24x-6x-12)=0
We get rid of parentheses
12x^2+24x-6x-12=0
We add all the numbers together, and all the variables
12x^2+18x-12=0
a = 12; b = 18; c = -12;
Δ = b2-4ac
Δ = 182-4·12·(-12)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-30}{2*12}=\frac{-48}{24} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+30}{2*12}=\frac{12}{24} =1/2 $

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