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(6x-3)(4+5x)=0
We add all the numbers together, and all the variables
(6x-3)(5x+4)=0
We multiply parentheses ..
(+30x^2+24x-15x-12)=0
We get rid of parentheses
30x^2+24x-15x-12=0
We add all the numbers together, and all the variables
30x^2+9x-12=0
a = 30; b = 9; c = -12;
Δ = b2-4ac
Δ = 92-4·30·(-12)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-39}{2*30}=\frac{-48}{60} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+39}{2*30}=\frac{30}{60} =1/2 $
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