(6x-3)(4x+6)=0

Solution for (6x-3)(4x+6)=0 equation:

(6x-3)(4x+6)=0

We multiply parentheses ..

(+24x^2+36x-12x-18)=0

We get rid of parentheses

24x^2+36x-12x-18=0

We add all the numbers together, and all the variables

24x^2+24x-18=0

a = 24; b = 24; c = -18;
Δ = b2-4ac
Δ = 242-4·24·(-18)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-48}{2*24}=\frac{-72}{48}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+48}{2*24}=\frac{24}{48}
=1/2
$