(6x-3)(4x=33)

Solution for (6x-3)(4x=33) equation:

(6x-3)(4x=33)

We move all terms to the left:

(6x-3)(4x-(33))=0

We multiply parentheses ..

(+24x^2-198x-12x+99)=0

We get rid of parentheses

24x^2-198x-12x+99=0

We add all the numbers together, and all the variables

24x^2-210x+99=0

a = 24; b = -210; c = +99;
Δ = b2-4ac
Δ = -2102-4·24·99
Δ = 34596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{34596}=186$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-210)-186}{2*24}=\frac{24}{48}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-210)+186}{2*24}=\frac{396}{48}
=8+1/4
$