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(6x-3)(6x-3)-(4x-11)(4x-11)=0
We multiply parentheses ..
(+36x^2-18x-18x+9)-(4x-11)(4x-11)=0
We get rid of parentheses
36x^2-18x-18x-(4x-11)(4x-11)+9=0
We multiply parentheses ..
36x^2-(+16x^2-44x-44x+121)-18x-18x+9=0
We add all the numbers together, and all the variables
36x^2-(+16x^2-44x-44x+121)-36x+9=0
We get rid of parentheses
36x^2-16x^2+44x+44x-36x-121+9=0
We add all the numbers together, and all the variables
20x^2+52x-112=0
a = 20; b = 52; c = -112;
Δ = b2-4ac
Δ = 522-4·20·(-112)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-108}{2*20}=\frac{-160}{40} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+108}{2*20}=\frac{56}{40} =1+2/5 $
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