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(6x-3)/(x+1)+1=0
Domain of the equation: (x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
(6x-3)+1*(x+1)=0
We get rid of parentheses
6x+1*(x+1)-3=0
We move all terms containing x to the left, all other terms to the right
6x+1*(x+1)=3
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