(6x-3)2-(2x-7)2=0

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Solution for (6x-3)2-(2x-7)2=0 equation: 



(6x-3)2-(2x-7)2=0

We multiply parentheses

12x-4x-6+14=0

We add all the numbers together, and all the variables

8x+8=0

We move all terms containing x to the left, all other terms to the right

8x=-8

x=-8/8

x=-1

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