(6x-3)2/3+6=15

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Solution for (6x-3)2/3+6=15 equation: 



(6x-3)2/3+6=15

We move all terms to the left:

(6x-3)2/3+6-(15)=0

We add all the numbers together, and all the variables

(6x-3)2/3-9=0

We multiply all the terms by the denominator


(6x-3)2-9*3=0

We add all the numbers together, and all the variables

(6x-3)2-27=0

We multiply parentheses

12x-6-27=0

We add all the numbers together, and all the variables

12x-33=0

We move all terms containing x to the left, all other terms to the right

12x=33

x=33/12

x=2+3/4

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