(6x-3)=(6x-4)/2

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Solution for (6x-3)=(6x-4)/2 equation: 



(6x-3)=(6x-4)/2

We move all terms to the left:

(6x-3)-((6x-4)/2)=0

We get rid of parentheses

6x-((6x-4)/2)-3=0

We multiply all the terms by the denominator


6x*2)-((6x-4)-3*2)=0

We add all the numbers together, and all the variables

6x*2)-((6x-4)=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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