(6x-35)=19+(4x-20)

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Solution for (6x-35)=19+(4x-20) equation: 



(6x-35)=19+(4x-20)

We move all terms to the left:

(6x-35)-(19+(4x-20))=0

We get rid of parentheses

6x-(19+(4x-20))-35=0



We calculate terms in parentheses: -(19+(4x-20)), so:

19+(4x-20)

determiningTheFunctionDomain
(4x-20)+19

We get rid of parentheses

4x-20+19

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We get rid of parentheses

6x-4x+1-35=0

We add all the numbers together, and all the variables

2x-34=0

We move all terms containing x to the left, all other terms to the right

2x=34

x=34/2

x=17

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