(6x-4)-8=(17-x)-8

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Solution for (6x-4)-8=(17-x)-8 equation:



(6x-4)-8=(17-x)-8
We move all terms to the left:
(6x-4)-8-((17-x)-8)=0
We add all the numbers together, and all the variables
(6x-4)-((-1x+17)-8)-8=0
We get rid of parentheses
6x-((-1x+17)-8)-4-8=0
We calculate terms in parentheses: -((-1x+17)-8), so:
(-1x+17)-8
We get rid of parentheses
-1x+17-8
We add all the numbers together, and all the variables
-1x+9
Back to the equation:
-(-1x+9)
We add all the numbers together, and all the variables
6x-(-1x+9)-12=0
We get rid of parentheses
6x+1x-9-12=0
We add all the numbers together, and all the variables
7x-21=0
We move all terms containing x to the left, all other terms to the right
7x=21
x=21/7
x=3

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