(6x-4)/(9x-1)=(2x+5)/(3x+10)

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Solution for (6x-4)/(9x-1)=(2x+5)/(3x+10) equation:


D( x )

3*x+10 = 0

9*x-1 = 0

3*x+10 = 0

3*x+10 = 0

3*x+10 = 0 // - 10

3*x = -10 // : 3

x = -10/3

9*x-1 = 0

9*x-1 = 0

9*x-1 = 0 // + 1

9*x = 1 // : 9

x = 1/9

x in (-oo:-10/3) U (-10/3:1/9) U (1/9:+oo)

(6*x-4)/(9*x-1) = (2*x+5)/(3*x+10) // - (2*x+5)/(3*x+10)

(6*x-4)/(9*x-1)-((2*x+5)/(3*x+10)) = 0

(6*x-4)/(9*x-1)+(-1*(2*x+5))/(3*x+10) = 0

((6*x-4)*(3*x+10))/((9*x-1)*(3*x+10))+(-1*(2*x+5)*(9*x-1))/((9*x-1)*(3*x+10)) = 0

(6*x-4)*(3*x+10)-1*(2*x+5)*(9*x-1) = 0

5*x-35 = 0

(5*x-35)/((9*x-1)*(3*x+10)) = 0

(5*x-35)/((9*x-1)*(3*x+10)) = 0 // * (9*x-1)*(3*x+10)

5*x-35 = 0

5*x-35 = 0 // + 35

5*x = 35 // : 5

x = 35/5

x = 7

x = 7

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