(6x-4)/3=12

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Solution for (6x-4)/3=12 equation: 



(6x-4)/3=12

We move all terms to the left:

(6x-4)/3-(12)=0

We multiply all the terms by the denominator


(6x-4)-12*3=0

We add all the numbers together, and all the variables

(6x-4)-36=0

We get rid of parentheses

6x-4-36=0

We add all the numbers together, and all the variables

6x-40=0

We move all terms containing x to the left, all other terms to the right

6x=40

x=40/6

x=6+2/3

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