(6x-4)=(x+11)+(2x+2)

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Solution for (6x-4)=(x+11)+(2x+2) equation: 



(6x-4)=(x+11)+(2x+2)

We move all terms to the left:

(6x-4)-((x+11)+(2x+2))=0

We get rid of parentheses

6x-((x+11)+(2x+2))-4=0



We calculate terms in parentheses: -((x+11)+(2x+2)), so:

(x+11)+(2x+2)

We get rid of parentheses

x+2x+11+2

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We get rid of parentheses

6x-3x-13-4=0

We add all the numbers together, and all the variables

3x-17=0

We move all terms containing x to the left, all other terms to the right

3x=17

x=17/3

x=5+2/3

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