(6x-4)=8(3x-2)

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Solution for (6x-4)=8(3x-2) equation: 



(6x-4)=8(3x-2)

We move all terms to the left:

(6x-4)-(8(3x-2))=0

We get rid of parentheses

6x-(8(3x-2))-4=0



We calculate terms in parentheses: -(8(3x-2)), so:

8(3x-2)

We multiply parentheses

24x-16

Back to the equation:

-(24x-16)



We get rid of parentheses

6x-24x+16-4=0

We add all the numbers together, and all the variables

-18x+12=0

We move all terms containing x to the left, all other terms to the right

-18x=-12

x=-12/-18

x=2/3

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