(6x-4)=8(3x-2)

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Solution for (6x-4)=8(3x-2) equation:



(6x-4)=8(3x-2)
We move all terms to the left:
(6x-4)-(8(3x-2))=0
We get rid of parentheses
6x-(8(3x-2))-4=0
We calculate terms in parentheses: -(8(3x-2)), so:
8(3x-2)
We multiply parentheses
24x-16
Back to the equation:
-(24x-16)
We get rid of parentheses
6x-24x+16-4=0
We add all the numbers together, and all the variables
-18x+12=0
We move all terms containing x to the left, all other terms to the right
-18x=-12
x=-12/-18
x=2/3

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