(6x-40=-22,x)

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Solution for (6x-40=-22,x) equation: 



(6x-40=-22.x)

We move all terms to the left:

(6x-40-(-22.x))=0

We add all the numbers together, and all the variables

(6x-40-(-22x))=0



We calculate terms in parentheses: +(6x-40-(-22x)), so:

6x-40-(-22x)

determiningTheFunctionDomain
6x-(-22x)-40

We get rid of parentheses

6x+22x-40

We add all the numbers together, and all the variables

28x-40

Back to the equation:

+(28x-40)



We get rid of parentheses

28x-40=0

We move all terms containing x to the left, all other terms to the right

28x=40

x=40/28

x=1+3/7

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