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(6x-42)(x+28)=60
We move all terms to the left:
(6x-42)(x+28)-(60)=0
We multiply parentheses ..
(+6x^2+168x-42x-1176)-60=0
We get rid of parentheses
6x^2+168x-42x-1176-60=0
We add all the numbers together, and all the variables
6x^2+126x-1236=0
a = 6; b = 126; c = -1236;
Δ = b2-4ac
Δ = 1262-4·6·(-1236)
Δ = 45540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{45540}=\sqrt{36*1265}=\sqrt{36}*\sqrt{1265}=6\sqrt{1265}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-6\sqrt{1265}}{2*6}=\frac{-126-6\sqrt{1265}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+6\sqrt{1265}}{2*6}=\frac{-126+6\sqrt{1265}}{12} $
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