If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(6x-5)(2x+1)=0
We multiply parentheses ..
(+12x^2+6x-10x-5)=0
We get rid of parentheses
12x^2+6x-10x-5=0
We add all the numbers together, and all the variables
12x^2-4x-5=0
a = 12; b = -4; c = -5;
Δ = b2-4ac
Δ = -42-4·12·(-5)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-16}{2*12}=\frac{-12}{24} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+16}{2*12}=\frac{20}{24} =5/6 $
| 9-3x-1=9 | | 3(9x+8)=4((8x-9) | | -8x²-16=0 | | (3x+5)^2x+1=(6x+2)^2x+1 | | 4b+2b+3b−2=16 | | -14-8x=-( | | 12+5x-8=12x+14 | | 28+8x=8(x=3)+2 | | 9x−1=26 | | 12x+48=79 | | 5b+40=12b | | -13+b=3b-1 | | 8x−8=44 | | (8x-25)=(7x-5)=180 | | -2-7z=-19-2z-6z | | 5^2x+5^x+1-50=0 | | X+4+3x=18 | | 6x-2(3x+8)=-16 | | A40=-1191,d=-30 | | 20+13c=5+12c | | 23x-(5x+10)=15x+24 | | ((x-48)^{1/2})^{2}=x^{0} | | 20+.50x=2x | | -12-d=d | | Ax+5=13 | | A1=28,d=10* | | 535x=55+x | | 3^(1-6x)=4x | | 4x+13=25* | | 35+x=55x | | 9-3r=-2r-3-5r | | -2.7=6+3c |