(6x-5)(2x+6)=0

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Solution for (6x-5)(2x+6)=0 equation:



(6x-5)(2x+6)=0
We multiply parentheses ..
(+12x^2+36x-10x-30)=0
We get rid of parentheses
12x^2+36x-10x-30=0
We add all the numbers together, and all the variables
12x^2+26x-30=0
a = 12; b = 26; c = -30;
Δ = b2-4ac
Δ = 262-4·12·(-30)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-46}{2*12}=\frac{-72}{24} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+46}{2*12}=\frac{20}{24} =5/6 $

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