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(6x-5)(3x-1)=0
We multiply parentheses ..
(+18x^2-6x-15x+5)=0
We get rid of parentheses
18x^2-6x-15x+5=0
We add all the numbers together, and all the variables
18x^2-21x+5=0
a = 18; b = -21; c = +5;
Δ = b2-4ac
Δ = -212-4·18·5
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-9}{2*18}=\frac{12}{36} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+9}{2*18}=\frac{30}{36} =5/6 $
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