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(6x-5)(5x+12)=0
We multiply parentheses ..
(+30x^2+72x-25x-60)=0
We get rid of parentheses
30x^2+72x-25x-60=0
We add all the numbers together, and all the variables
30x^2+47x-60=0
a = 30; b = 47; c = -60;
Δ = b2-4ac
Δ = 472-4·30·(-60)
Δ = 9409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9409}=97$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-97}{2*30}=\frac{-144}{60} =-2+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+97}{2*30}=\frac{50}{60} =5/6 $
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