(6x-5)*(2-3x)=(3-9x)*(2x-1)

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Solution for (6x-5)*(2-3x)=(3-9x)*(2x-1) equation: 



(6x-5)(2-3x)=(3-9x)(2x-1)

We move all terms to the left:

(6x-5)(2-3x)-((3-9x)(2x-1))=0

We add all the numbers together, and all the variables

(6x-5)(-3x+2)-((-9x+3)(2x-1))=0

We multiply parentheses ..

(-18x^2+12x+15x-10)-((-9x+3)(2x-1))=0



We calculate terms in parentheses: -((-9x+3)(2x-1)), so:

(-9x+3)(2x-1)

We multiply parentheses ..

(-18x^2+9x+6x-3)

We get rid of parentheses

-18x^2+9x+6x-3

We add all the numbers together, and all the variables

-18x^2+15x-3

Back to the equation:

-(-18x^2+15x-3)



We get rid of parentheses

-18x^2+18x^2+12x+15x-15x-10+3=0

We add all the numbers together, and all the variables

12x-7=0

We move all terms containing x to the left, all other terms to the right

12x=7

x=7/12

x=7/12

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