(6x-5)+(4x-2)+x=180

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Solution for (6x-5)+(4x-2)+x=180 equation: 



(6x-5)+(4x-2)+x=180

We move all terms to the left:

(6x-5)+(4x-2)+x-(180)=0

We add all the numbers together, and all the variables

x+(6x-5)+(4x-2)-180=0

We get rid of parentheses

x+6x+4x-5-2-180=0

We add all the numbers together, and all the variables

11x-187=0

We move all terms containing x to the left, all other terms to the right

11x=187

x=187/11

x=17

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