(6x-5)+(8-4x)=15-2(x-1)

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Solution for (6x-5)+(8-4x)=15-2(x-1) equation: 



(6x-5)+(8-4x)=15-2(x-1)

We move all terms to the left:

(6x-5)+(8-4x)-(15-2(x-1))=0

We add all the numbers together, and all the variables

(6x-5)+(-4x+8)-(15-2(x-1))=0

We get rid of parentheses

6x-4x-(15-2(x-1))-5+8=0



We calculate terms in parentheses: -(15-2(x-1)), so:

15-2(x-1)

determiningTheFunctionDomain
-2(x-1)+15

We multiply parentheses

-2x+2+15

We add all the numbers together, and all the variables

-2x+17

Back to the equation:

-(-2x+17)



We add all the numbers together, and all the variables

2x-(-2x+17)+3=0

We get rid of parentheses

2x+2x-17+3=0

We add all the numbers together, and all the variables

4x-14=0

We move all terms containing x to the left, all other terms to the right

4x=14

x=14/4

x=3+1/2

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