(6x-5)-(3x+1)=(3x+1)-(x+3)

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Solution for (6x-5)-(3x+1)=(3x+1)-(x+3) equation:



(6x-5)-(3x+1)=(3x+1)-(x+3)
We move all terms to the left:
(6x-5)-(3x+1)-((3x+1)-(x+3))=0
We get rid of parentheses
6x-3x-((3x+1)-(x+3))-5-1=0
We calculate terms in parentheses: -((3x+1)-(x+3)), so:
(3x+1)-(x+3)
We get rid of parentheses
3x-x+1-3
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
We add all the numbers together, and all the variables
3x-(2x-2)-6=0
We get rid of parentheses
3x-2x+2-6=0
We add all the numbers together, and all the variables
x-4=0
We move all terms containing x to the left, all other terms to the right
x=4

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